sum of two consecutive odd integer is 128
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Answered by
1
since the two numbers are odd, and consecutive, they have a difference of 2.
suppose the smaller integer of the two =x
128=x+(x+2)
=2x+2
so as to find the smaller odd integer, you need to find the value of x:
128−2=2x+2−2
=126=2x
1262=2x2=63
x=63
63 is the smaller number, so the bigger number is 63+2=65
pls mark as brainlest answer
suppose the smaller integer of the two =x
128=x+(x+2)
=2x+2
so as to find the smaller odd integer, you need to find the value of x:
128−2=2x+2−2
=126=2x
1262=2x2=63
x=63
63 is the smaller number, so the bigger number is 63+2=65
pls mark as brainlest answer
Answered by
4
Answer- Let 1st no. be x and 2nd no. be x+2.
ATC, x+x+2= 128
2x= 126
x= 126/2= 63
x+2= 63+2= 65So, the two numbers are 63 and 65.
Please mark as the BRAINLIEST answer if helpful.
ATC, x+x+2= 128
2x= 126
x= 126/2= 63
x+2= 63+2= 65So, the two numbers are 63 and 65.
Please mark as the BRAINLIEST answer if helpful.
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