sum of two consecutive odd number is 68 find the no
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Step-by-step explanation:
Let one of the smallest odd no be x therefore another consecutive odd no would be x+2 .
given sum of no is 68 ie
x+(x+2)=68
2x+2=68
2x=66
x=33
therefore two no are 33 and 35
Answered by
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Let 2 consecutive odd numbers be
1st=(2x+7) 1st no=2x+1
2nd=(2x+3) (2x*16)+1
(2x+1)+(2x+3)=68 32+1=33
2x+1+2x+3=68 2nd no=2x+3
2x+2x+1+3=68 (2*16)+3
4x+4=68 32+3=35
4x=68-4
4x=64
X=64/4
X=16
Answer- 2 consecutive nos are 33,35
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