sum of two consecutive terms are 97 when we divide smaller terms by bigger terms so the remainder is 12 and quotient is 4 find the sum no.
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By using Carl Gauss's clever formula, (n / 2)(first number + last number) = sum, where n is the number of integers, we learned how to add consecutive numbers quickly. We now know that the sum of the pairs in consecutive numbers starting with the first and last numbers is equal.
Hope it helps and make sure to mark it BRAINLIEST!
Answered by
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By using Carl Gauss's clever formula, (n / 2)(first number + last number) = sum, where n is the number of integers, we learned how to add consecutive numbers quickly. We now know that the sum of the pairs in consecutive numbers starting with the first and last numbers is equal.
Hope it helps and make sure to mark it BRAINLIEST!
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