Question

sum of two consequetive whole number is 63 .find the smaller number​

Answer 1

Given :

Sum of two consecutive whole number is 63.

$\:$

To Find :

The smaller number ?

$\:$

Explanation :

Sum of two consecutive whole numbers is 63.

Let,

• One number = x
• Other number = x-1

Now,

$\sf \implies Sum \: of \: two \: consecutive \: whole \: numbers = 63 \:$

$\sf \implies \: (x) \: + (x - 1) = 63$

$\sf \implies \: 2x - 1 = 63$

$\sf \implies \: 2x = 63 + 1$

$\sf \implies \: 2x = 64$

$\displaystyle\sf \implies \: x = \cancel\frac{64}{2}$

$\textbf{ \textsf{ \red{⟹ \: \large \underline{\boxed{\textbf{ \textsf{x = 32}}}}}}}$

∴ One number is x = 32

∴ Other number is x-1 = 32-1 = 31

$\:$

Verification :

$\sf \implies Sum \: of \: two \: consecutive \: whole \: numbers = 63 \:$

Substitute 32 in the place of x

$\sf \implies \: (x) \: + (x - 1) = 63$

$\sf \implies \: (32) \: + (32- 1) = 63$

$\sf \implies \: 32 \: + 31= 63$

$\bf \implies \: 63= 63$

L.H.S = R.H.S

∵ Hence verified !!

$\:$

Note :

Suppose x = 1

Then the other number = x-1 = 0

Here, 0 consider as whole number

So, I have taken x and x-1

Because the two consecutive numbers are whole numbers.

$\:$

$\:$

# Thank you ❣️