sum of two digit number and number obtain the reversing digit is 121 find the number if it's unite place digit is greater than the ten place digita
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Bhai tera question incomplete hai
Dekh you have mentioned only one condition
so by that we get 10y+X+10x+y=121
so 11x+11y=121
therefore X+y=11
the second condition is incomplete
you said that the digit in units place is greater than the tens place
so X>y
but you didn't mention by how much
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