sum of two digit number and number obtained by reversing the digits is always divisible by
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As for the number (10x+y) and the reversed number (x+10y)…they will add up to (11x+11y) which will always be divisible by 11
As for the number (10x+y) and the reversed number (x+10y)…they will add up to (11x+11y) which will always be divisible by 11
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