Question

sum of two digit number and the number obtained by reversing the order of its digits 121 and the two digit is differ by 3 find the number​

Answer 1

Answer:

Ahh I hate maths problems

Answer 2

Answer:

Correct answer is 74 or 47

Let the two digit number be 10x + y

On reversing its digits, we get the number

10y + x

Given, (10x + y) + (10y + x) = 121

11x + 11y = 121

=> x + y = 11 --- (1)

Given, x - y = 3 -- (2) Adding (1), (2), we get 2x = 14=> x = 7

Substituting

X = 7 in the equation (2), we get 7 - y =

3 => y = 4

Hence, the number is 74 or 47

A 47 or 74