Question

sum of two digit number is 8 if the digits are interchanged new number is 10 more than double the original number find the number​

Answer 1

Answer:

26

Step-by-step explanation:

Let the digit at one's place be =x

Let the digit at ten's place be =y

So the number becomes =10y+x

According to the question,

x+y=8 ------ eq1

2(10y+x)=10x+y-10

On solving,

19y-8x=-10 -----eq2,

Adding eq1 and eq2, we get

y=2

Putting value of y in eq1 we get,

x=6

So the number becomes=10y+x=26