sum of two digit number is 9 if the digits are reversed the new numbers so form increase by 27 find the number
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let the number be x and y
hence,
10x+y=9...1eq
let the new number be v
10y+x=v+27...2eq
by 1st equation x=9-y/10
put in 2nd equation
10y+9-y/10=v+27
10y+9-y/10=v+27
9+9y/10=v+27
9+9y=10(v+27)
9+9y=10v+270
v=9+9y-270/10
something like that
....
by
good night
hence,
10x+y=9...1eq
let the new number be v
10y+x=v+27...2eq
by 1st equation x=9-y/10
put in 2nd equation
10y+9-y/10=v+27
10y+9-y/10=v+27
9+9y/10=v+27
9+9y=10(v+27)
9+9y=10v+270
v=9+9y-270/10
something like that
....
by
good night
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