sum of two digit number which will divided by 4 should leave remainder 4
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How many two digit numbers leaves the remainder "1" when divided by four?
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7
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12 Answers
Karthik Kolle, Once in love with numbers :P
Answered December 15, 2016
This question can be solved by using AP.
First two digit number which leaves a remainder of 1 when divided by 4 is 13. Let this term be denoted by a
Similarly the next two digit number leaves a when divided by 4 is 17. So the common difference is 17–13 = 4. Let this common difference be denoted by d
In the same pattern last two digit number which leaves a remainder of 1 when divided by 4 is 97. Let this term be denoted by l
And we know that last term of an AP is given by l=a+((n-1)*d) where n is the number of terms in the sequence which is to be found out.
Substituting the values we get,
97=13+((n-1 )*4)
So. 97–13=84=(n-1)*4
So n-1 =84/4 = 21
So n= 22.
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