Question

sum of two digit of a two digit number is 10. the number obtained by reversing the digit is 36 greater than the original number find the number. ​

Answer 1

Step-by-step explanation:

Let the number be 10x+ y, where x is the digit in the 10’s place and y is the digit in the unit’s place

We have,

x + y = 10 ————————————{I}

Now,

(10x + y) - (10y + x) = 36 ………………..[digits reversed = 10y + x]

or, 9x - 9y = 36

or, x - y = 4 —————————— {II}

Adding {I} and {II},

2x = 14,

or x = 7

Hence, y = 10 - 7 = 3

So, the number is 73 [ 10 * 7 + 3]