sum of two digit of a two digit number is 9 when we interchange the digit it is found that the resulting number is greater than the original number by 27
what is the two digit number
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Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 39 =27
27 = 27 (correct)
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 39 =27
27 = 27 (correct)
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