sum of two digited number and the number obtained by reversing the digits is 66. If the digits
of the number differ by 2. Find the number. How many such numbers are there
Answers
Answered by
8
Let the 1st digit be x and 2nd digit be y
First no. = 10x + y
When the digits are reversed,
It becomes = 10y + x
Then,
According to the question, digits differ by 2
If x - y = 2, then, {By elimination, solving (1) and (2)}
x = 4
y = 2
∴ Number = 42
If y – x = 2, then, {By elimination, solving (1) and (3)}
x = 2
y = 4
∴ Number = 24
There are two such numbers = 42 and 24
Answered by
19
Step-by-step explanation:
sum of two digited number and the number obtained by reversing the digits is 66. If the digits
of the number differ by 2. Find the number. How many such numbers are there
GIVEN
sum of two digited number and the number obtained by reversing the digits is 66.If the digits of the number differ by 2.
∴ Number (2−digit) =10×x+y
Sum of 2−digit and reverse of it
Digits differ by 2
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