Question

sum of two digits number is 12.if the
digits are reveresd, the new number, so formed increase by
36 find the number​

Answer 1

Answer: 48

Step-by-step explanation:

let one's place = y

ten's place = x

Number = 10x + y

Acc to question,

x + y = 12 ➡️1

When digits are reversed ,

New Number = 10y + x

Acc to question ,

New No. = Original no. + 36

10y + x = 10x + y + 36

9y - 9x = 36

y - x = 4 ➡️ eq2

Adding eq 1 and 2

2y = 16

y = 8 , Put in eq 1

x = 4

Number = 48

Answer 2

Answer:

48

Step-by-step explanation:

Let digits be x and y

number= 10x+y

x+y=12....EQ1

10y+x=10x+y+36

9x-9y=-36

x-y=-4....EQ1

From EQ1 and EQ2

x=4,y=8

number= 10*4+8=48