sum of two digits of a 2 digit number is 12. if the digits are reversed, the new number, so formed increase by 36. find the number
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Answer: Tens digit of number = x
Ones digit of number = 12-x
Original Number = 10x+12-x
= 9x+12
Reversed Number = 10(12-x)+x
= 120-10x+x
= 120-9x
According to the question,
9x+12+36=120-9x
9x+48=120-9x
9x+9x=120-48
18x=72
x=72/18
x=4
Original Number = 9x+12
= 9(4)+12
= 36+12
= 48 is the number
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