Question

Sum of two digits of a 2-digit number is 12. If the digits are reversed, the new number so formed
increase by 36. Find the number
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Answer 1

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➪ let one's place = y

ten's place = x

Number = 10x + y

➪ Acc to question,

x + y = 12 ➡️1

➪ When digits are reversed ,

New Number = 10y + x

✈︎ Acc to question ,

New No. = Original no. + 36

10y + x = 10x + y + 36

9y - 9x = 36

y - x = 4 ➡️ eq2

➪ Adding eq 1 and 2

2y = 16

y = 8 , Put in eq 1

x = 4

Number = 48

Answer 2

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➪ let one's place = y

ten's place = x

Number = 10x + y

➪ Acc to question,

x + y = 12 ➡️1

➪ When digits are reversed ,

New Number = 10y + x

✈︎ Acc to question ,

New No. = Original no. + 36

10y + x = 10x + y + 36

9y - 9x = 36

y - x = 4 ➡️ eq2

➪ Adding eq 1 and 2

2y = 16

y = 8 , Put in eq 1

x = 4

Number = 48

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