Question

Sum of two digits of a 2-digit number is 12. If the digits are reversed, the new number, so formed increase by 36. Find the number.​

Answer 1

Answer is attached above.

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Answer 2

Answer:

Thanks for the points❤❤

Step-by-step explanation:

Let x be the unit digit and y be tens digit.

Then the original number be 10x+y.

Value of the number with reversed digits is 10y+x.

As per question, we have

x+y=12 ....(1)

If the digits are reversed, the digits is greater than the original number by 36.

Therefore, 10y+x=10x+y+36

⇒9x−9y=−36....(2)

Multiply equation (1) by 9, we get

9x+9y=108 ....(3)

Add equations (2)and (3),

18x=72

⇒x=4

Substitute this value in equation (1), we get

4+y=12⇒y=8

Therefore, the original number is 10x+y=10×4+8=48..