Question

Sum of two digits of a number is 12.If the position of two digits has changed,then the new number increased to 18 then the previous number.What is the number?

Answer 1

Answer:

36884444477488844114

Answer 2

Answer:

number is 57

Step-by-step explanation:

let the tens digit = x

and the once digit = y

A.T.Q

x + y = 12 ------------(1)

our number is in form 10x + y

if change the digit

then new number is 10y + x

10x + y + 18 = 10y + x

10x - x + y - 10y = -18

9x - 9y = -18

divide by 9

x - y = -2 -----------(2)

on adding eq. 1 and 2

x + y = 12

x - y = -2

2x = 10

x = 5

put x in eq 1

x + y = 12

5 + y = 12

y = 12 - 5

y = 7

then the number is 10x + y

= 10 × 5 + 7

= 57