Question

Sum of two digits of a two digit no. is 9. When we interchange the digits it is found that the resulting new no. Is greater than the original number by 27.
What is the two digit number

Answer 1

Answer:

Let,the one's digit be x and ten's digit be 9-x.

It is given that sum of two digit is 9.

Firstly, we will find the original no.-.

10(9-x)+1(x). =90-10x+x. or 90-9x.

After Interchanging the digits:-

The one's digit is 9-x and the tens digit is x.

Then the new no:-

10(x)+1(9-x)

10(x)+1(9-x)=10x+9-x

10(x)+1(9-x)=10x+9-xor 9x+9.

A.T.Q.-

The resulting new no.is greater than the original no.by 27.

Therefore, 9x+9=27+90-9x

or, 9x+9x=27+90-9

18x=117-9

18x=108

x=108/18

=6.

So,the ten's digit=(9-x)

=9-6 =3.

And the one's digit is x

=6

HENCE,THE ORIGINAL NO.IS 36.

I HOPE THIS ANSWER WILL HELP YOU!...