sum of two digits of a two digit number is 7 if the digits are reversed the new number so formed is increased by 27. Find the number
Answers
Let the -
- one's digit number be N
- ten's digit number be M
Sum of two digits of a two digit number is 7. (Means, the sum of one's digit number and ten's digit number is 7)
According to question,
⇒ M + N = 7
⇒ M = 7 - N ...(1)
If the digits are revered. In actual number is 10M + N. If we revered then M will take the place of N and vice-versa.
So,
If the digits are reversed the new number so formed is increased by 27.
According to question,
⇒ 10M + N + 27 = 10N + M
⇒ 10M - M + N - 10N = - 27
⇒ 9M - 9N = - 27
Take 9 common from both sides
⇒ 9(M - N) = -9(3)
⇒ M - N = - 3
⇒ 7 - N - N = - 3 [From (1)]
⇒ 7 - 2N = - 3
⇒ - 2N = - 3 - 7
⇒ -2N = - 10
⇒ N = 5
Substitute value of N = 5 in (1)
⇒ M = 7 - 5
⇒ M = 2
Number = 10M + N
Substitute value of M = 2 and N = 5 above
⇒ 10(2) + 5
⇒ 20 + 5
⇒ 25
•°• Number is 25.
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Verification :-
From above we have -
- ten's digit number = M = 2
- one's digit number = N = 5
Substitute value of M and N in eq (1)
→ 5 = 7 - 2
→ 5 = 5
Answer:
The original number is 25.
Step-by-step explanation:
Let the unit digit be y and tens digit be x.
Given :
◐ Sum of the digits of the number or the the sum of x and y is 7.
◐ By reversing the digits, the new number which is formed is 27 more than the original.
As we know,
Any two digit no. can be written in the form of 10a + b ( ab ).
So,
The number is 10x + y... (original)
And its reversed form is 10y + x.
since x + y = 7
y = 7 - x ___ ( I )
Solution :
[ 27 is added in the original to balance the equation ]
(10x + y) + 27 = (10y + x)___( II )
[Substituting the value of equation i in equation ii]
10x + (7 - x) + 27 = 10(7 - x) + x
9x + 34 = 70 - 10x + x
9x + 34 = 70 - 9x
18x = 36
x = 2
We got our tens digit as 2 (x)
And acc. to the equation 1 y = 7 - x
so our unit digit is 5.
So, the number is 25.