Question

sum of two integer is 88. if the greater is divided by the smaller, the quotient is 5 and the remainder is 10. find the greater integer.​

Answer 1

let the integers be x and (88-x).

so,

5 × x + 10 = (88-x)

or, 5x + 10 = 88 -x

or, 6x = 78

or, x = 13

therefore, greater integer 88-13 = 75

Answer 2

Given,

The sum of two integers = 88

The greater is divided by the smaller, the quotient is 5 and the remainder is 10.

To Find,

The greater integer =?

Solution,

We can solve the question using the following steps:

Let x be the greater and y be the smaller integer.

$x + y =88$ -------- (1)

Since $dividend = divisor*quotient + remainder$,

$x = 5y +10$ -------- (2)    

In the above equation, x is divided by y. The quotient and the remainder are 5 and 10 respectively.

Substituting equation (2) in (1),

$5y + 10 + y = 88$

$6y + 10 = 88$

$6y = 78$

$y = 13$

Now, to find the value of x, we substitute the value of y in the second equation.

$x = 5y + 10 = 5*13 + 10 = 75$

Therefore, $x = 75, y = 13$

Hence, the greater integer is 75.