Question

sum of two integers is 126. The larger is 18 less than 5 times the smaller​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

let smaller be y

larger be 5y-18

5y-18+y=126

6y-18= 126

6y = 126+18

6y = 144

y = 144/6

y = 24

larger number be 24×5-18 = 102