Question

sum of two is 74.one of the number is 10 more than the other. what are the numbes?​

Answer 1

Step-by-step explanation:

Let smaller no be (x)

so greater no be (x+10)

ATQ =>

x+x+10 = 74

2x = 64

x = 32

So, x = 32 is solution

Answer 2

Answer:

Step-by-step explanation:LET THE FIRST NO. TO BE=X

AND SECOND NO. TO BE =X+10 (because second no. Is 10 more than the one)

A.T.Q

X + X+ 10 = 74

X+X =74-10

2X = 64

X = 32

SO, FIRST NO. = X= 32

SECOND NO. = X+ 10 =32+10 = 42 .

*hope this will help you*