sum of two mumbers is 35 and there difference is 13 .find tje number
Answers
Answered by
7
Hey Mate!
Given,
Sum of two numbers = 35
Their difference = 13
let the numbers be x and y
x + y = 35 ------(1)
x - y = 13 -------(2)
Solve eq - 1 & 2
x + y = 35
x - y = 13
-------------
2x = 48
x = 48/2
x = 24
24 + y = 35
y = 35 - 24
y = 11
Therefore, the numbers are 24 and 11
HOPE THIS HELPS U...
Given,
Sum of two numbers = 35
Their difference = 13
let the numbers be x and y
x + y = 35 ------(1)
x - y = 13 -------(2)
Solve eq - 1 & 2
x + y = 35
x - y = 13
-------------
2x = 48
x = 48/2
x = 24
24 + y = 35
y = 35 - 24
y = 11
Therefore, the numbers are 24 and 11
HOPE THIS HELPS U...
krishnashri2003:
thats good ans pls ans my next question
Answered by
5
Hey mate:
````````````````````
Here is yr answer
_____________________________
Sum of the two integers is 35
=> x + y = 35 -----( * )
there Difference is 13
=> x - y = 13 ------(**)
Add (*) and (**)
x + y + x - y = 35 + 13
2x = 48
x = 48/2
x = 24
Substitute the x value in (*)
x + y = 35
24 + y =35
y = 35 - 24
y = 11
Therefore, the integers are 24 and 11.
Hope it hlpzzz..
````````````````````
Here is yr answer
_____________________________
Sum of the two integers is 35
=> x + y = 35 -----( * )
there Difference is 13
=> x - y = 13 ------(**)
Add (*) and (**)
x + y + x - y = 35 + 13
2x = 48
x = 48/2
x = 24
Substitute the x value in (*)
x + y = 35
24 + y =35
y = 35 - 24
y = 11
Therefore, the integers are 24 and 11.
Hope it hlpzzz..
Similar questions