Question

sum of two natural number is 8 and difference of their reciprocal is2/5 find the numbers​

Answer 1

Answer:

let's take x and y.x+y=8,and,1/x + 1/y=2/5

now solve for x and y.thats it!

Answer 2

Solution✐✐✐✐✐✐

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➣let the numbers be X and Y ...where X>Y

now.therefore...(1/X)<(1/Y)

❍condition 1

➾X+Y=8

➾Y=8-X

❍condition 2

$= > \frac{1}{y} - \frac{1}{x} = \frac{2}{5} \\ = > 5x - 5y - 2xy = 0 \\ = > 5x - 5(8 - x) - 2x(8 - x) = 0 \\ = > 5x - 40 + 5x - 16x + 2x {}^{2} = 0 \\ = > 2x {}^{2} - 6x - 40 = 0 \\ = > x {}^{2} - 3x - 20 = 0 \\ \\ x = \frac{3 + \sqrt{9 + 80} }{2 \times 1} = \frac{3 + \sqrt{89} }{2} \\ y = 8 - \frac{3 + \sqrt{89} }{2} = \frac{13 - \sqrt{89} }{2}$

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