Question

Sum of two no is 108 .if one exceeds other by 42.Find the no

Answer 1

Given: Sum of two no is 108 and one exceeds other by 42.

Let one number be x

The other number will be x + 42

According to condition:

x + x + 42 = 108

2x + 42 = 108

2x = 108 - 42

2x = 66

x = 66/2

x = 33

Hence, one number, x = 33

Second number = 4 + 42

= 33 + 42

Second number = 75

Answer 2

Step-by-step explanation:

Let one number be x

The other number will be X+42

According to question

》X+x+42=108

》2x+42=108

》2x=108-42

》2x=66

》x=66/2

》x=33

》one numbers x=33

》second number =4+42

》33+42

》second number are 75.