Question

Sum of
two no. is 41 and their difference is
5. Find the number.
9​

Answer 1

Answer:

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Step-by-step explanation:

Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 41. In other words, x plus y equals 41 and can be written as equation A:

x + y = 41

The difference between x and y is 5. In other words, x minus y equals 5 and can be written as equation B:

x - y = 5

Now solve equation B for x to get the revised equation B:

x - y = 5

x = 5 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 41

5 + y + y = 41

5 + 2y = 41

2y = 36

y = 18

Now we know y is 18. Which means that we can substitute y for 18 in equation A and solve for x:

x + y = 41

x + 18 = 41

X = 23

Summary: The sum of two numbers is 41 and their difference is 5. What are the two numbers? Answer: 23 and 18 as proven here:

Sum: 23 + 18 = 41

Difference: 23 - 18 = 5

Answer 2

Step-by-step explanation:

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