Sum of two no. Is 81.one is twice the other.the two nos. are
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Let x and y be the two nos.
According to the question , we have
x + y = 81 - eq(1)
2x = y
x = y/2 - eq(2)
Substituting the value of x in eq(1), we get
x + y = 81
y/2 + y = 81
(y + 2y)/2 = 81
3y/2 = 81
3y = 81 × 2
3y = 162
y = 162/3
= 54
then, x = 54/2
= 27
∴ The two nos. are 27 and 54 .
Hope it helps u.
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