Question

Sum of two number 74 . One of the number is 10 , more than the other , find the number.

perimeter of the rectangle is 13cm and its breadth 2 3/4 cm.Find its length.

Answer 1

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Question(1)

Sum of two number 74 . One of the number is 10 , more than the other , find the number.

Answer:

$\sf = x + y = 74 \\ \sf = x = y + 10 \\ \sf = y + 10 + y = 74 \\ \sf = 2y = 74 - 10 \sf \\ = 2y = 64 \sf \\ \sf = y = \frac{64}{2} = 32 \sf \\ \sf= x = 32 + 10 \sf \\ \sf= 42$

Question(2)

Perimeter of the rectangle is 13cm and its breadth 2 3/4 cm. Find its length.

Answer:

$\sf = 2(l + b) = 13 \\ \sf=2(l + \frac{11}{4} ) = 13 \sf \\ = 2(l + \frac{22}{4} ) = 13 \\ \sf= 2l = 13 - \frac{22}{4} \\ \sf = 2l = \frac{52 - 22}{4} = \frac{30}{4} \\ \sf = l = \frac{30}{2} \times \frac{1}{2} \\ \sf = l = \frac{15}{4} \\ \sf= \frac{3}{4}$