Question

sum of two number and the difference of the two are 498 and 302 respectively .Find the numbers​

Answer 1

Answer:

Lets assume that numbers as x and (x-302)

The sum of the numbers are 498

Therefore

x+(x-302) = 498

Lets remove the brackets

x+x-302 = 498

x+x = 498 + 302

2x = 800

x = 800/2

= 400

x-302 = 400 - 302

= 98

So the numbers are 400 and 98

Sum = 400 + 98 = 498

Difference = 400 - 98 = 302

Answer 2

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

Given that: Sum of two number and the difference of the two are 498 and 302 respectively. Means,

• Sum of 2 numbers = 498
• Difference of 2 numbers = 302

To find: The original numbers.

Solution: 98 and 400 are the original numbers.

Assumption: Let the two numbers be x and y respectively. Means,

• 1st number is x
• 2nd number is y

Full Solution:

~ As it's said that

• Sum of 2 numbers = 498
• Difference of 2 numbers = 302

Henceforth,

• x+y = 498...Equation 1
• x-y = 302...Equation 2

• (Now we have to add ...Equation 1 and ...Equation 2 together)

• (Remember, LHS will with LHS and the RHS will add with RHS)

››› x+y+(x-y) = 302+498

››› x+y+x-y= 302+498

• (- = + or + = -)

• (- and + cancel each other)

››› x+x = 302+498

››› 2x = 302+498

››› 2x = 800

››› x = 800/2

• (÷ = × or × = ÷)

››› x = 400

Henceforth, the values of x we get as 400. 400 is 1st number

››› 400+y = 498

››› y = 498-400

››› y = 98

Henceforth, the values of y we get as 98. 98 is 2nd number