sum of two number is 108 . 8 times one of the number is 9 more than the other find the number
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Let the first number = x
Let the second number = y
According to question :
8x = y + 9
x = y + 9 / 8 ...(1)
Now x + y = 108 ...(2)
put the value of x in equation (2)
y + 9 / 8 + y = 108
y + 9 + 8y / 8 = 108
y + 9 + 8y = 108 × 8
9y + 9 = 864
9y = 864 - 9
9y = 855
y = 855 / 9
y = 95
put the value of y in equation (1)
x = 95 + 9 / 8
x = 95 + 9 / 8
x = 104 / 8
x = 13
The first number = x = 13
The second number = y = 95
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Let the second number = y
According to question :
8x = y + 9
x = y + 9 / 8 ...(1)
Now x + y = 108 ...(2)
put the value of x in equation (2)
y + 9 / 8 + y = 108
y + 9 + 8y / 8 = 108
y + 9 + 8y = 108 × 8
9y + 9 = 864
9y = 864 - 9
9y = 855
y = 855 / 9
y = 95
put the value of y in equation (1)
x = 95 + 9 / 8
x = 95 + 9 / 8
x = 104 / 8
x = 13
The first number = x = 13
The second number = y = 95
Hope you like it please mark as brainliest and follow me if you like my answer.
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