Sum of two number is 128 and difference is 16 find numbers
Answers
Answered by
3
let the two numbers be x and y
according to the question
x+y=128 equation 1
x-y=16 equation 2
addition both the equations
2x=144
x=72
putting value of x in equation 1
72+y=128
y=128-72
y=56
hope it helps you
according to the question
x+y=128 equation 1
x-y=16 equation 2
addition both the equations
2x=144
x=72
putting value of x in equation 1
72+y=128
y=128-72
y=56
hope it helps you
Answered by
1
SOLUTION :
LET the 2 no.s be X and Y respectively
therefore
( X + Y ) =128 (equation 1 )
and
( X - Y )=16 (equation 2 )
now adding equations 1 and 2 we get
(X+Y)+(X+Y)=128+16
OR. 2X=144
OR. X=72
therefore Y=128-X
OR. Y = 128 -72
OR. Y = 56
ANS.
X=72, Y = 56
HOPE THIS HELPS
LET the 2 no.s be X and Y respectively
therefore
( X + Y ) =128 (equation 1 )
and
( X - Y )=16 (equation 2 )
now adding equations 1 and 2 we get
(X+Y)+(X+Y)=128+16
OR. 2X=144
OR. X=72
therefore Y=128-X
OR. Y = 128 -72
OR. Y = 56
ANS.
X=72, Y = 56
HOPE THIS HELPS
Rahul4554:
hi
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