sum of two number is 4 more than the twice of difference of the two numbers if one of the two numbers is three more tha the other number then numbers are
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Let the two numbers be x and y respectively,
According to the question,
==> sum of the numbers is 4 more than the twice of difference of the two numbers
==> x + y = 2(x - y) + 4
==> x + y = 2x - 2y + 4
==> x - 3y = -4 ...(1)
Also,
==> One of the two numbers is three more than the other number
==> x = y + 3 { Assuming, x > y }
==> x - y = 3 ...(2)
Subtracting (2) from (1)
==> x - y - x + 3y = 3 - ( -4)
==> 2y = 7
==> y = 7/2
Putting y = 7/2 in (2)
==> x - y = 3
==> x = 3 + y
==> x = 3 + 7/2
==> x = 13/2
Hence, the required numbers are 7/2 and 13/2
∴ Option A is correct.
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