Question

Sum of two number is 45 and greater number is twice the smaller number.Find the number​

Answer 1

$\boxed{question}$

Sum of two number is 45 and the greatest number is twice the smaller number . Find the number.

$\boxed{answer}$

$\sf\large\underline\purple{Given:)}$

• Sum of two numbers is 45
• the greatest number is twice the smaller number.

$\sf\large\underline\purple{to find}$

• find the number

$\sf\large\underline\purple{solution:)}$

let the number be x,

so smallest number = x

greatest number = 2x

sum = 45

x + 2x = 45

3x = 45

$x = \frac{45}{3} = 15$

if the value of x = 15

so smallest number = 15

greatest number = 2 × 15 = 30 .

$\sf\large\underline\purple{let verify :)}$

according to the question, sum = first number + second number

45 = 15+ 30

45 = 45

the sum of 15 and 30 is 45

so , it is verified ✓

Hence, we do it ✓

Answer 2

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${ \huge{ \underline{ \underline{ \frak{ \red{Required \: answer: }}}}}}$

the two numbers be x and y.

where, x >y

--》x + y = 45 --》[1]

--》x = 2y ..(2)--》[2]

from [1]

--》x + y = 45

--》2y+y = 45--》[from 2]

--》3y = 45

--》y = 15

put this value in equation [1], we get

--》x + 15 = 45

--》x = 30

hence the two number is 30 and 15

${ \huge{ \sf{ \boxed{ \red{30 \:, 15}}}}}$

${ \huge{ \underline{ \underline{ \frak{ \red{Verify:}}}}}}$

--》30 + 15 = 45

--》= 45...

Hence Verifed...

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