Question

Sum of two number is 58 and
one number exceeds another by 12.find the numbers​

Answer 1

Answer:

Here is ur answer

Step-by-step explanation:

$let \: one \: number \: b \: x$

$let \: another \: number \: be \: x + 12$

$x + x + 12 =58$

$2x + 12=58$

$x= \frac{58 - 12}{2}$

$x= \frac{46}{2}$

$x=23$

$if \: x \: =23$

$then \: x + 12$

$→23 + 12$

$→35$

Answer 2

Answer :

The numbers are :

• 23
• 35

Step-by-step explanation :

To Find,

• The numbers .... ?

Solution,

Given that,

• One number exceeds another by 12
• Sum of two numbers is 58

Let us assume the number as x and the number which exceeds another by 12 as x + 12

Therefore,

Given that,

: ⟹ x + ( x + 12 ) = 58

: ⟹ x + x + 12 = 58

: ⟹ 2x + 12 = 58

: ⟹ 2x = 58 - 12

: ⟹ 2x = 46

: ⟹ x = 46 / 2

: ⟹ x = 23

The value of x is 23.

Therefore, the numbers are,

The number which we assumed as x is

• x = 23

The other number which we assumed as the number which exceeds another by 12 as x + 12 is

• x + 12 = 25

Hence, the numbers are 23 and 25.

Now, Verification

Given that,

⟹ x + ( x + 12 ) = 58

By putting the values,

: ⟹ 23 + ( 23 + 12 ) = 58

: ⟹ 22 + 35 = 58

: ⟹ 58 = 58

L.H.S = R.H.S

Hence, Verified !