Math, asked by Anonymous, 4 months ago

Sum of two number is 58 and
one number exceeds another by 12.find the numbers​

Answers

Answered by sainiinswag
1

Answer:

First number = 35

2nd number = 23

Attachments:
Answered by MrSanju0123
179

 {\huge{\boxed{ \huge{ \boxed{\bf{\underline{ \underline{ \pink{ \bigstar{Answer}{ \bigstar}}}}}}}}}}

Two numbers are 23,35 respectively.

Step-by-step explanation:

 \huge{  \bf{ \underline{ \pink{ Given}}}}

  • Sum of two numbers is 58.

  • One number exceeds the other number by 12.

 \huge{  \bf{ \underline{ \pink{To  \: Find }}}}

  • The two numbers

 \huge{  \bf{ \underline{ \pink{ SolutioN}}}}

  • Let's assume one of the numbers as x

  • So, the other number = x + 12

  • In the question it is given that the sum of two numbers are 58.

  • So,

  •  \bf \: x + x + 12 = 58

  •  \bf \: 2x + 12 = 58

  •  \bf2x = 58 - 12

  •  \bf \: 2x = 46

  •   \bf \: x =  \frac{46}{2}

  •  \bf \: x = 23

So, we got x as 23

So other number = x + 12 = 23 + 12 = 35.

♤___________________♤

 {\huge {\boxed{ \bf{ \underline{ \pink{ Checking}}}}}}

  • To check our answer we have to add the numbers and check whether our sum is 58.

  • We got the numbers as 23, 35

  • So,

  • 23 + 35 = 58

  • 58 = 58

So, our Answer is correct ✔✔

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