sum of two number is 74 . one of the number is 10 more than the other .what are the number s?
Answers
Answered by
0
Answer:
Sum of two numbers is 74
Let one number be x
Other number is x+10
Equating:
x+x+10=74
2x+10=74
2x=74-10
2x=64
x=64/2
x=32
Therefore,
One number is 32
Other number is 32+10=42
Answered by
0
Answer:
let x be req. no.
then, another no. = 74-x
a/q, x-(74-x)=10
=> 2x = 84
=> x=42
so, req. numbers are 42 & (74-42)=32
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