Question

sum of two number is 74 . one of the number is 10 more than the other .what are the number s?​

Answer 1

Answer:

Sum of two numbers is 74

Let one number be x

Other number is x+10

Equating:

x+x+10=74

2x+10=74

2x=74-10

2x=64

x=64/2

x=32

Therefore,

One number is 32

Other number is 32+10=42

Answer 2

Answer:

let x be req. no.

then, another no. = 74-x

a/q, x-(74-x)=10

=> 2x = 84

=> x=42

so, req. numbers are 42 & (74-42)=32