Question

Sum of two number is 80. If the larger number exceeds four times the the smaller number by 5 find them.
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Answer 1

Step-by-step explanation:

let larger no be x

small no. be y

x+y=80--------(1)

x=4y+5

hence,

x-4y=5---------(2)

sub (1) and (2)

we get,5y=75

y=15

now, put y =15 in eq(1)

x+15=80

there fore x=65

so x =65 and y =17

Answer 2

Smaller number is 15

Larger number is 65

let x be larger no. and y be smaller no.

Then, x+y=80

Also larger no.=4(smaller no.)+5

i.e., x=4y+5

=>4y+5+y=80

=>5y+5=80

=>y=15 and therefore x=65.

(Verification: from answer method

Assuming smaller no. as 15 then 4*15+5=65 which is the largest no. Also their sum is 80.)