Question

Sum of two numbers=24 दो संख्याओं का योग= 24 HCF=8 LCM=16 Find the sum of their inverse . इनके व्युत्क्रमो का योग=?

Answer 1

Step-by-step explanation:

$(a + b) = 24$

$(a × b) = LCM * HCF$

$(a × b) = 16 * 8 = 128$

$Now ,$

$a^-¹ + b^-¹$

$\frac{1}{a} + \frac{1}{b}$

$\frac{(a + b)}{a × b}$

$\frac{24}{128}$

$\frac{3}{16}$