Question

Sum of two numbers 40. If one exceeds the other by 18,find the number.

Answer 1

Answer:

sum of 2 no =40

then ,

let the no be x

A/Q=(x+18)+x=40

2x=40-18

x=32/2

x=16

1st no=x=16

2nd no=x+18=16+18=34

16+34=40

Step-by-step explanation:

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