Math, asked by Pamtant, 10 months ago

Sum of two numbers are 528 and their hcf 48 find the pairs

Answers

Answered by raghav1776
0

Step-by-step explanation:

Lcm=528/48 =11

Let firsr number be x and second number be y

X+y=528

Y=528-x

First nymber= lcm*hcf/ second number

X=11*48/528-x

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