Question

sum of two numbers is 100 if one number exceeds the other number by 20 find the number​

Answer 1

let the first no. be x

and the second no. be x+20

acoording to your question

x+x+20 =100

2x+20 =100

2x=100-20

2x=80

x=80/2

x=40

thus the first no. which is x is 40

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and the second no. which exceeds over 20 is x+20

40+20

60

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i hope it helps you

if are you still not cleared then ask in comment section .

Answer 2

Answer:

let the first no be =  x

the another number will be =x+20

according to question,sum of the number is 100

x+x+20=100

2x=80

x=40

first number=40

other number x+20=40+20=60

Step-by-step explanation: