Question

sum of two numbers is 101 and one number exceeds another by 7.find the two numbers​

Answer 1

Answer :-

Given :-

• sum of 2 numbers is 101
• their difference is 7

To find :-

• Those 2 numbers

Solution :-

Let the 2 numbers be x and x + 7

According to the question ;

》x + x +7 = 101

》2x + 7 = 101

》2x = 101 - 7

》2x = 94

》x = 94/2 = 47

so one number is 47 and the number is 47 + 7 = 54 ..

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hope it helps !!

btw , telugu na?

Answer 2

Answer:

Step-by-step explanation:

sum of 2 numbers is 101

their difference is 7

To find :-

Those 2 numbers

Solution :-

Let the 2 numbers be x and x + 7

According to the question :-

》x + x +7 = 101

》2x + 7 = 101

》2x = 101 - 7

》2x = 94

》x = 94/2 = 47

so one number is 47 and the number is 47 + 7 = 54