Sum of two numbers is 103. If greater number is divided by smaller number then the quotient is 2 and the remainder is 19. Then find the numbers.
Answers
Answered by
131
❍ Let's say, the greater number be x and the smaller number be y respectively.
By given C O N D I T I O N :
Case – I)
- The sum of both greater and smaller number is 103.
Therefore,
➠ x + y = 103 ⠀⠀⠀⠀⠀⠀ —eq( I ).
⠀⠀⠀⠀⠀⠀
Also,
⠀⠀⠀⠀⠀⠀
Case – II)
- If the greater number is divided by the smaller number then the Quotient is 2 and the Remainder is 19.
Therefore,
➠ x = 2y + 19 ⠀⠀⠀⠀⠀⠀ —eq( I I ).
⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀
⟫ Substituting eq ( II ) in eq ( I ) :
⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀
⟫ Now, from eq ( II ) :
⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀
V E R I F I C A T I O N :
- It is given that, the sum of both greater and smaller number is 103. So, let's verify :
⠀⠀⠀⠀⠀⠀
Therefore,
⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀
⠀⠀⠀
Answered by
135
Answer:
- 75 and 28
Step-by-step explanation:
Given
- Sum of two numbers = 103
- If greater number if divided by smaller number.
- Quotient = 2
- Remainder = 19
To find
- The numbers
Solution
↪ Let the numbers be x and y and y is greater among them.
↪ If greater number if divided by smaller number,
- y/x
↪ Quotient,
- 2
↪ Remainder,
- 19
We know,
- Dividend = Divisor × Quotient + Remainder
We get,
- y = 2x + 19
ATP,
- Sum of two numbers = 103
- x + 2x + 19 = 103
- 3x + 19 = 103
- 3x = 103 - 19
- 3x = 84
- x = 84/3
- x = 28
Hence , the value of x is 28.
Now,
- x + y = 103
- 28 + y = 103
- y = 103 - 28
- y = 75
Hence, the greater number (y) = 75
and, the smaller number (x) = 28
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