sum of two numbers is 11 and sum of their reciprocals is 11/28 Find the number?
Answers
Answered by
100
let the two numbers are x and y.
therefore according to question their sum is 11
x+y=11---------i
now.
sum of their reciprocal is 11/28
1/x+1/y=11/28
x+y/by=11/28
28(x+y)=11xy-------ii
xy=28.
now
(x-y)^2=x^2+y^2-2xy
(x-y) ^2=(x+y)^2-4xy
(x-y) ^2=121-112
x-y=3--------iii
on adding I and IIi, we get
x+y+x-y=3+11
2x=14
x=7
on putting x=7 in first equation we get
y=4
if my answer is helpful for you then please mark as brain list
therefore according to question their sum is 11
x+y=11---------i
now.
sum of their reciprocal is 11/28
1/x+1/y=11/28
x+y/by=11/28
28(x+y)=11xy-------ii
xy=28.
now
(x-y)^2=x^2+y^2-2xy
(x-y) ^2=(x+y)^2-4xy
(x-y) ^2=121-112
x-y=3--------iii
on adding I and IIi, we get
x+y+x-y=3+11
2x=14
x=7
on putting x=7 in first equation we get
y=4
if my answer is helpful for you then please mark as brain list
SIMRAN8122:
thankyou soo much ji
Answered by
73
Answer:
Step-by-step explanation:
Given that -
The sum of two numbers is 11 and the sum of their reciprocal is 11/28.
Let the numbers be x and y respectively.
Sum of numbers is 11.
⇒ x + y = 11.... (i)
⇒ y = 11 - x .... (ii)
Sum of reciprocals is 11/28.
⇒ .... (iii)
Now, on solving (iii),
Putting the value of (i) and (ii) here, we get -
Hence, the required numbers are 7 and 4.
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