sum of two numbers is 11 and their product is 28 what are the numbers
Answers
Answered by
6
Answer:
First number is 7 and second is 4
Answered by
5
Answer:
the numbers are 7 and 4
Step-by-step explanation:
here a+b=11,a×b=28
therefore a=11-b
(11-b)b=28
11b-b²=28
-b²+11b-28=0
-b²+(7+4)b-28=0
-b²+7b+4b-28=0
therefore, (b-7)(b-4) =0
b-7=0
b=7
b-4=0
b=4
therefore, a=11-b
a=11-7
a=4
therefore, a=11-b
a=11-4
a=7
here a×b=28
7×4=28
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