Sum of two numbers is 17, whereas sum of their squares is 145. What is the product of the two numbers?
Answers
Answered by
9
<================================>
Solution==>>
<================================>
x +y =17 also y = 17-x
x² + y² = 145
x² +(17-x)² = 145
x² +289 -34x +x² = 145
2x² -34x +144 = 0
(2x -16)(x-9) = 0
x =8
So if x =8 then y = 9
So , Product is
8×9=72
<================================>
Verification==>
Their sum is 17
8+7=17
and
sum of square is 145
(8)²+(9)²
64+81=145
<================================>
Hope it is helpful to you
PLS MARK IT AS BRAINLIEST!!!!
<================================>
Solution==>>
<================================>
x +y =17 also y = 17-x
x² + y² = 145
x² +(17-x)² = 145
x² +289 -34x +x² = 145
2x² -34x +144 = 0
(2x -16)(x-9) = 0
x =8
So if x =8 then y = 9
So , Product is
8×9=72
<================================>
Verification==>
Their sum is 17
8+7=17
and
sum of square is 145
(8)²+(9)²
64+81=145
<================================>
Hope it is helpful to you
PLS MARK IT AS BRAINLIEST!!!!
<================================>
Answered by
2
Let the two numbers be x and y
x + y = 17
x^2 + y^2 = 145
x^2 + (17-x)^2 = 145
x^2 + x^2 - 34x + 289 = 145
2x^2 - 34x + 144 = 0
x^2 - 17x + 72 = 0
x^2 - 9x - 8x + 72 = 0
x(x - 9) -8 (x-9) = 0
x = 8 or x = 9
If x = 8, y = 9
When x = 9, y = 8
Product = 8*9 = 72.
Similar questions