Sum of two numbers is 20 and their product is 40. Find the sum of their reciprocals
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let 2 no.s be a,b
A.T.Q.
a+b=20
or a=20-b
and
a×b=40
(20-b)b=40
20b-20b^2=40
solving which,, we get b= -1,2
hence we can have a=21,18
now..1/a+1/b=1/21-1=-20/21
or 1/a+1/b=1/18+1/2=5/9
and these two are our possible answers
A.T.Q.
a+b=20
or a=20-b
and
a×b=40
(20-b)b=40
20b-20b^2=40
solving which,, we get b= -1,2
hence we can have a=21,18
now..1/a+1/b=1/21-1=-20/21
or 1/a+1/b=1/18+1/2=5/9
and these two are our possible answers
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