Question

sum of two numbers is 21 and the sum of their squares is 261. Find the numbers​

Answer 1

plz mark me brainlest

I hope help you

Answer 2

$hey \: mate \: \\ - - - - - - - - \\ given \: \\ 1 equation = > x + y = 21 \\ or \\ y = 21 - x \\ 2 equation = > \\ {x}^{2} + {y}^{2} = \: 261 \\ or \\ {x}^{2} + ({21 - x})^{2} = 261 \\ from \: equation \: 2 \\ \\ {x}^{2} + {21}^{2} + {x}^{2} - 2 \times 21 \times x \: = 261 \\ {x}^{2} + 441 + {x}^{2} - 42x = 261 \\ {x}^{2} + 441 - 261 + {x}^{2} - 42x = 0 \\ {x}^{2} + 180 + {x}^{2} - 42x = 0 \\ {2x }^{2} - 42x + 180 = 0 \\ by \: prime \: factorisation \: method \\ {2x}^{2} - 12x - 30x + 180 = 0 \\ 2x(x - 6) - 30(x - 6) = 0 \\ => (x - 6) = 0 \: and \: (2x - 30) = 0 \\ \\ hence \: x \: = 6 \: and \: 15 \\ from \: equation \: 1 \\ 15 + y \: = 21 \\ y \: = 21 - 15 = 6 21 - 6 = 15 hence , X = 6,15 and Y = 15,6 \\ - - - - - - - - - - - - - \\ mark \: me \: as \: a \: brainlist \: follow \: me \: plzzzzzz$