Question

Sum of two numbers is 24 and one number exceeds another by 4. Express the data in linear

equation form.​

Answer 1

SoluTion:

Let one number be x.

According to the question,

other number = x + 4

Also, it is given that, sum of two numbers is 24.

$\therefore$ x + x + 4 = 24

$\mapsto$ 2x = 24 - 4

$\mapsto$ 2x = 20

$\mapsto$ x = $\sf{\dfrac{20}{2}}$

$\red{\mapsto}$ $\sf{\blue{x\:=\:10}}$

Hence, numbers are 10 and 14.

$\rule{200}2$

VerificaTion:

Put x = 10 in translation.

$\mapsto$ 10 + 10 + 4 = 24

$\mapsto$ 24 = 24

Hence verified.

Answer 2

$\huge {\red{\mathfrak{Question :-}}}$

• Sum of two numbers is 24 and one number exceeds another by 4. Express the data in linear equation form.

$\huge {\pink{\mathfrak{Solution :-}}}$

$\underline{\bold{Given:}}$

• Sum of two numbers = 24

$\underline{\bold{To\:Find:}}$

• The numbers.

Let one number be x.

Then, the other number = x+4

In linear equation form :

$\implies x + (x + 4) = 24\\ \\ \implies x+x + 4= 24 \\ \\ \implies 2x + 4 = 24$

Now we are going to find the numbers :

Atq,

$\implies x + (x + 4) = 24 \\ \\ \implies x + x + 4= 24 \\ \\ \implies 2x + 4 = 24 \\ \\ \implies 2x = 24 - 4 \\ \\ \implies 2x = 20 \\ \\ \implies x = \dfrac{20}{2} \\ \\ \implies x = 10$

$\green {\tt {\therefore {The\:numbers\: are\:10\: and\:10+4=14.}}}$

$\rule{197}{1}$

$\huge{\underline{\bold{Verification:}}}}$

We know that sum of two numbers =24,

so:

$\implies one\: number+other\:number = 24\\ \\ \implies 10+14=24\\ \\ \implies 24=24\\ \\ \implies LHS=RHS$

$\rule {195}{2}$